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If A + B + C = π, prove that
sin 2A + sin 2B – sin 2C = 4cos A cos B sin C
cos 2A – cos 2B – cos 2C = -1 + 4 cos A sin B sin C
cos 2A – cos 2B + cos 2C = 1 – 4sin A cos B sin C
sin (B + C – A) + sin (C + A – B) – sin (A + B – C) = 4cos A cos B sin C
cos2 A + cos2 B + cos2 C = 1 – 2cos A cos B cos C
sin2 A – sin2 B + sin2 C = 2sin A cos B sin C
tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C