Let g(x) be the inverse of an invertible function f(x) which is derivable at x = 3. If f(3) = 9 and f’(3) = 9, write the value of g’(9).


From the definition of invertible function,


g(f(x)) = x …(i)


So, g(f(3)) = 3, i.e., g(9) = 3


Now, differentiating both sides of equation (i) w.r.t. x using the Chain Rule of Differentiation, we get –


g’(f(x)). f’(x) = 1 …(ii)


Plugging in x = 3 in equation (ii) gives us –


g’(f(3)).f’(3) = 1


or, g’(9).9 = 1


i.e., g’(9) = 1/9 (Ans)


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