Choose the correct alternative in the following:
If f(x) = |x – 3| and g(x) = fof(x), then for x > 10, g’(x) is equal to
= ||x – 3| – 3|
Since we have given x > 10 then |x – 3| = (x – 3)
∴ g(x) = |(x – 3) – 3| = |x – 6|
Since we have given x > 10 then |x – 6| = (x – 6)
∴ g(x) = (x – 6)