The electric field in a region is given by with E₀ = 2.0 × 10³ N C^–1. Find the flux of this field through a rectangular surface of area 0.2 m² parallel to the y–z plane.

Given:

Electric field :

E₀=2.0× 10³ N/C

Surface area of plane=0.2m²

The plane is parallel to y-z plane. The normal to this plane is parallel to x-axis. Therefore, area vector for this plane is given by 0.2m²î

∴ ΔS=0.2m²î

We know that,

Flux of electric field through a surface of area ΔS is given by dot product of electric field E⃗ with surface area ΔS⃗

⇒ Nm²/C

⇒ Nm²/C

⇒ Nm²/C (putting the value of E₀)

Nm²/C

Therefore the flux of this electric field through the given plane surface is 240Nm²/C.