The pH of a solution of a strong acid is 5.0. What will be the pH of the solution obtained after diluting the given solution a 100 times?

Given pH=5.0, we know that;

As we dilute the solution, the concentration of the solution will reduce by how much times we are diluting it.

So as we are diluting the solution 100 times, the concentration of the acidic solution will decrease by 100 times i.e.

pH = -log[H⁺]

[H⁺]=10^-5 mol/L

Diluting it 100 times

So, the new concentration will be = 10^-7 mol/L

And, pH Value will be = pH = -log [H⁺]

=-log [10^-7] = 7

Hence the pH after diluting solution hundred times will be 7.