A block of mass 250 g slides down an incline of inclination 370 with a uniform speed. Find the work done against the friction as the block slides through 1.0 m.

Given mass m= 0.25kg, inclination θ =37° , displacement = 1m Now weight = mg= 0.25× 10=2.5N (g=10m/)

Now from the F.B.D we find that the force against is the component of weight along the incline = So work done against the friction force on the block = F× s



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