A bag contains 6 red balls and some blue balls. If the probability of drawing a blue ball from the bag is twice that of a red ball, find the number of blue balls in the bag.
Given: number of red balls = 6
Let number of blue balls be x
Total number of possible outcomes, n(S) = 6 + x
Number of favorable outcomes = n(E)
P(blue ball) = 2P(red ball)
⇒ x = 12
∴ number of blue balls = 12
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