Prove that the points (3, 0), (6, 4) and (- 1, 3) are vertices of a right-angled isosceles triangle.
Vertices of a triangle ABC are: A(3, 0), B(6, 4) and C (- 1, 3)
Length of side AB =
Length of side AB =
= 
= 
units
Length of side BC =
= 
= 
units
Length of side AC =
= 
= 
units
Since AB = AC, therefore triangle is an isosceles.
BC2 = AB2 + AC2
(√50)2 = (√25)2 + (√25)2
50 = 25 + 25
50 = 50
Since BC2 = AB2 + AC2; therefore given triangle is right angled triangle.
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