If an angle of a parallelogram is two-thirds of its adjacent angle, the smallest angle of the parallelogram is


Let A = x°, B =


Since the sum of any two adjacent angles of a parallelogram is 180°,


A + B = 180°


x° + = 180°


= 180°


= 54


x° = 108°


A = 108°


B = 72°


Also, B + C = 180° [Since, B and C are adjacent angles]


72° + C = 180°


C = (180° - 72°) = 108°


Further, C + D = 180° [Since, C and D are adjacent angles]


108° + D = 180°


D = (180° - 108°) = 72°


Therefore, smallest angle of the parallelogram is 72°.

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