Solve the following pairs of equations
43x + 67y = –24, 67x + 43y = 24
Given pair of linear equations is
…(i)
and …(ii)
On multiplying Eq. (i) by 43 and Eq. (ii) by 67 and then subtracting both of them, we get
Now, put the value of x in Eq. (i), we get
Hence, the required values of x and y are 1 and - 1, respectively.