A die is thrown once. Find the probability of getting
(i) An even number
(ii) A number less than 5
(iii) A number greater than 2
(iv) A number between 3 and 6
(v) A number other than 3
(vi) The number 5.
When a die is thrown, all the possible outcomes are: 1, 2, 3, 4, 5, 6
Total number of outcomes = 6
(i) Let E be the event of getting an even number
Then, the favourable outcomes are: 2, 4, 6
Number of favourable outcomes = 3
∴ P (getting exactly one head) = P(E) = 3/6 = 1/2 or 50%
(ii) Let E be the event of getting a number less than 5
Then, the favourable outcomes are: 1, 2, 3, 4
Number of favourable outcomes =4
∴ P (getting number less than 5) =P (E) =4/6=2/3 or about 66.67%
(iii) Let E be the event of getting a number greater than 2
Then, the favourable outcomes are: 3, 4, 5, 6
Number of favourable outcomes are =4
∴ P (getting number greater than 2) = P (E) =4/6= 2/3 or 66.67%
(iv) Let E be the event of getting number between 3 and 6
Then, the favourable outcomes are: 4, 5,
Number of outcomes are = 2
∴ P (getting number between 3 and 6) = P (E) = 2/6 =1/3 or 33%
(v) Let A be the event of getting number other than 3
Then, the favourable outcomes are: 1, 2, 4, 5, 6
Number of outcomes are = 5
∴ P (getting number other than 3) = P (E) =5/6 or 83.33%
(vi) Let E be the event of getting number 5
Then, the favourable outcome is: 1
∴ P (getting exactly number 5) = P (E) = 1/6 or 16.67%