A die is thrown once. Find the probability of getting

(i) An even number


(ii) A number less than 5


(iii) A number greater than 2


(iv) A number between 3 and 6


(v) A number other than 3


(vi) The number 5.

When a die is thrown, all the possible outcomes are: 1, 2, 3, 4, 5, 6

Total number of outcomes = 6


(i) Let E be the event of getting an even number


Then, the favourable outcomes are: 2, 4, 6


Number of favourable outcomes = 3


P (getting exactly one head) = P(E) = 3/6 = 1/2 or 50%


(ii) Let E be the event of getting a number less than 5


Then, the favourable outcomes are: 1, 2, 3, 4


Number of favourable outcomes =4


P (getting number less than 5) =P (E) =4/6=2/3 or about 66.67%


(iii) Let E be the event of getting a number greater than 2


Then, the favourable outcomes are: 3, 4, 5, 6


Number of favourable outcomes are =4


P (getting number greater than 2) = P (E) =4/6= 2/3 or 66.67%


(iv) Let E be the event of getting number between 3 and 6


Then, the favourable outcomes are: 4, 5,


Number of outcomes are = 2


P (getting number between 3 and 6) = P (E) = 2/6 =1/3 or 33%


(v) Let A be the event of getting number other than 3


Then, the favourable outcomes are: 1, 2, 4, 5, 6


Number of outcomes are = 5


P (getting number other than 3) = P (E) =5/6 or 83.33%


(vi) Let E be the event of getting number 5


Then, the favourable outcome is: 1


P (getting exactly number 5) = P (E) = 1/6 or 16.67%


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