A game of chance consist of spinning an arrow, which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and these are equally likely outcomes. Find the probability that the arrow will point at any factor of 8.
Total numbers of elementary events are: 8
Let E be the event of getting the arrow pointing at any factor of 8
The favourable outcomes are: 1, 2, 4,
Then, the number of favourable events are = 3
∴ P (getting a factor of 8) = P (E) = 3/8