Find two numbers such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

Question

Philoid · Accepted Answer

Let the two numbers be x and y.

According to question -

2x + 3y = 92.....(1)

4x - 7y = 2.....(2)

From equation (1), we get -

x = (92 - 3y)/2.....(3)

Substituting the value of x in equation (2), we get -

⇒ 184 - 6y - 7y = 2

⇒ 13y = 182

∴ y = 14

substituting the value of y in equation (3), we get -

x = 25

Thus, the numbers are 25 and 14.