A sample of drinking water was found to be severely contaminated with chloroform (CHCl3) supposed to be a carcinogen. The level of contamination was 15 ppm (by mass):
(i) express this in percent by mass
(ii) determine the molality of chloroform in the water sample.
Given:
Level of contamination = 15 ppm [by mass]
To find: Mass Percentage and Molality
Formula:
Molality
Mass Percentage of Solute
Solution:
Calculation of Mass Percentage:
15 ppm means 15 parts of Chloroform in 106 parts of drinking water
⇒ Mass Percentage
= 1.5 × 10-3
Calculation of Molality:
⇒ Molecular Mass of Chloroform, CHCl3 = [12] + [1] + [35.5 × 3]
= 119.5 g
⇒ Number of Moles of Chloroform = [15 / 119.5]
= 0.1255 moles
Molality
= 1.255 × 10-4
Therefore the Mass Percentage is = 1.5 × 10-3 and the Molality of the solution is = 1.255 × 10-4 m.