The partial pressure of ethane over a solution containing 6.56 × 10^–3 g of ethane is 1 bar. If the solution contains 5.00 × 10^–2 g of ethane, then what shall be the partial pressure of the gas?

Given:

Mass of ethane in solution A = 6.56 × 10^–3 g

Partial pressure of solution A = 1 bar

Mass of ethane in solution B = 5.00 × 10^–2 g

To find: Partial Pressure of gas

Formula:

By Henry’s law:

Mass of dissolved gas M = k × P

Where

k = proportionality constant

P = Partial Pressure

Solution:

⇒ M₁ = k × P₁ ……………… [1]

⇒ M₂ = k × P₂ …………….. [2]

Dividing the [2] by [1], we get

P₂ = 7.62 bar

Therefore the partial pressure of the gas is 7.62 bar.