If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons would flow through the wire?
Current I = 0.5A
Time t = 2hrs = 2×60×60 = 7200 seconds
Charge Q = I×t
Q = 0.5×7200 = 3600 C
Charge carried by 1 mole of electrons (6.023×1023electrons) is equal to 96487C.
No of electrons = 6.023×1023 × 3600/96487
No of electrons = 2.25×1022 electrons.