Calculate the half life of a first order reaction from their rate constants given below:
(i) 200 s-1 (ii) 2 min-1 (iii) 4 years-1
Half life of first order reaction is, t1/2 = ln2/K where t1/2 is half life of first order reaction, K is rate constant of First order reaction.
(i) t1/2 = ln2/200 s-1
⇒ t1/2 = 0.693/200 s-1 (∵ ln2 = 0.693)
⇒ t1/2 = 0.003465 sec.
(ii) t1/2 = ln2/2 min-1
⇒ t1/2 = 0.693/2 min-1 (∵ ln2 = 0.693)
⇒ t1/2 = 0.3465 min
(iii) t1/2 = ln2/4 year-1
⇒ t1/2 = 0.693/4 years -1 (∵ ln2 = 0.693)
⇒ t1/2 = 0.17325 year.
Half life of 3 reactions are 0.003465 sec, 0.3465 min, 0.17325 year respectively.