Predict the number of unpaired electrons in the square planar Pt[(CN)4]2- ion.


In Pt[(CN)4]2- ion:

Overall charge balance:


X + 4(-1) = -2


X = + 2.


The oxidation state of Pt is + 2.


Since CN- is a strong field ligand, it causes pairing of the unpaired electrons.



Therefore, now the 2 unpaired electrons from 5d orbital get paired and it undergoes dsp2 hybridisation. It forms square planar geometry. Since all the electrons are paired,


No. of unpaired electrons = 0.


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