RS Aggarwal - Mathematics

Book: RS Aggarwal - Mathematics

Chapter: 10. Quadratic Equations

Subject: Maths - Class 10th

Q. No. 49 of Exercise 10F

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49

Solve: √3x2 + 10x – 8√3 = 0.

Using splitting middle term, the middle term of the general equation is divided in two such values that:

Product = a.c


For the given equation


using


=


And either of their sum or difference = b


=


Thus the two terms are


Difference =


Product =




√3 x(x + 4√3 )-2(x + 4√3) = 0


(√3 x-2)(x + 4√3) = 0




Hence roots of equation are


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