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Find the area of the major segment APB of a circle of radius 35 cm and ∠AOB = 90°, as shown in the given figure.
Given:
Radius of Circle = 35 cm
∠AOB = 90°
∵ Area of Sector = × πr2
= ×
× 35 × 35
= cm2
∵ ∆ AOB is right-angled triangle.
∴ Area of ∆ AOB = × OA × OB
= × 35 × 35
= cm2
Now, Area of Minor Segment ACB
= Area of Sector – Area of ∆AOB
= -
=
= 350 cm2
Area of Circle = πr2
= × 35 × 35
= 22 × 5 × 35
= 3850 cm2
Thus, Area of Major Segment = Area of Circle – Area of Minor Segment = 3850 – 350 = 3500 cm2
Hence, the area of the major segment is 3500 cm2.