Find the point on x-axis which is equidistant from points A(-1, 0) and B(5, 0).

Question

Philoid · Accepted Answer

Let the point on the x-axis which is equidistant from points A(-1,0) and B(5,0) i.e. the point which divides the line segment AB in the ratio 1:1 be C(x,0).

∴ m:n = 1:1

Recall that if (x,y) ≡ (a,b) then x = a and y = b

Let (x,y) ≡ (x,0)

(x₁,y₁) ≡ (-1,0)

and (x₂,y₂) ≡ (5,0)

Using Section Formula,

⇒ x = (4/2) = 2

Thus, the point on the x-axis which is equidistant from points A(-1,0) and B(5,0) is P(2,0).