Calculate the mass of sodium acetate (CH₃COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^–1.

Given:

Molecular Mass of Sodium Acetate = 82.0245g/mol

Molarity of sodium acetate = 0.375 M

0.375 molar solution of sodium acetate means 0.375g of sodium acetate dissolved in 1000ml of the solution.

But it is given in the question that the solution should be of 500ml.

So, 0.375g of CH₃COONa → 1000ml of solution

X g of CH₃COONa → 500ml of solution

X = [0.375×500]/1000

= 187.5/1000

= 0.1875 moles

Mass of Sodium acetate required to make 500ml solution = Number of moles of CH₃COONa × Molecular Mass of CH₃COONa

= 82.0245× 0.1875

= 15.379g

≈ 15.38g

Therefore 15.38g of CH₃COONa is required to make 500ml of solution.