Calculate the number of atoms in each of the following:
(i) 52 moles of Ar
(ii) 52 u of He
(iii) 52 g of He.
(i) According to Avogadro’s Law,
1 mole of Argon → 6.023×1023 atoms of Argon
So, 52 moles of Argon → X atoms of Argon
X =52×6.023×1023
=3.13196×1025
Therefore in 52 moles of Argon 3.13196×1025 atoms are present.
(ii) Atomic Mass of Helium [He] = 4 u
This means that mass of one atom of Helium is = 4 u
So, Number of atom of Helium contained in 52u = 52/4
= 13 atoms
Therefore, in 52u of Helium 13 atoms are present.
(iii) Atomic Mass of Helium [He] = 4 u
So, Number of Moles of Helium in 52g = 52/4
= 13 atoms
So, Number of atoms in 52g of Helium [He] = 13×6.023×1023
= 7.8299×1024
Therefore, in 52g of Helium 7.83×1024 atoms are present.