A concave lens has focal length of 20 cm. At what distance from the lens a 5 cm tall object be placed so that it forms an image at 15 cm from the lens? Also calculate the size of the image formed.


According to the question;

Object distance = u;


Image distance (v) = -15cm;


Focal length = -20cm


By lens formula;






u = -60cm.


Therefore, object is placed at 60 cm in front of lens.


Now;


Height of object h1= 5cm;


Magnification = =


Putting values of v and u


Magnification =




Height of image is 1.25 cm.


Positive sign means image is virtual.


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