An erect image three times the size of the object is formed with a concave mirror of radius of curvature 36 cm. What is the position of the image?
For an erect image, magnification is positive. Thus, m = 3 for an erect image three times the size of the object.
m = 3
For a concave mirror,
⇒v = -3u
Using Mirror formula,
Putting the value of v = -3u
v = -3u
⇒ v = 36 cm
Thus, the image is formed behind the mirror at a distance of 36 cm.