Differentiate each of the following functions from the first principal :
x2 ex
We have to find the derivative of x2ex with the first principle method, so,
f(x) = x2ex
by using the first principle formula, we get,
f ‘(x) = 
f ‘(x) = 
f ‘(x) = 
[By using (a+b)2 = a2+b2+2ab]
f ‘(x) = 
f ‘(x) = 
[By using limx→0 
= 1]
f ‘(x) = x2ex + limh→0 e(x+h) [h+2x]
f ‘(x) = x2ex + 2x ex
8