Find , when
y = e3x sin 4x 2x
Let y = e3x sin 4x 2x
Take log both sides:
⇒ log y = log (e3x sin 4x 2x)
⇒ log y = log (e3x ) + log (sin 4x) + log (2x)
⇒ log y = 3x log e+ log (sin 4x) + x log 2 {log xa = alog x}
⇒ log y = 3x + log (sin 4x) + x log 2 {log e = 1}
Differentiating with respect to x: