Find , when
y = xsin x + (sin x)x
let y = xsin x + (sin x)x
⇒ y = a + b
where a= xsin x; b = (sin x)x
a= xsin x
Taking log both the sides:
⇒ log a= log xsin x
⇒ log a= sin x log x
{log xa = alog x}
Differentiating with respect to x:
Put the value of a = xsin x :
b = (sin x)x
Taking log both the sides:
⇒ log b= log (sin x)x
⇒ log b= x log (sin x)
{log xa = alog x}
Differentiating with respect to x:
Put the value of b = (sin x)x :