Find , when
y = (tan x)cot x + (cot x)tan x
let y = (tan x)cot x + (cot x)tan x
⇒ y = a + b
where a= (tan x)cot x ; b = (cot x)tan x
a= (tan x)cot x
Taking log both the sides:
⇒ log a= log (tan x)cot x
⇒ log a= cot x log (tan x)
{log xa = alog x}
Differentiating with respect to x:
b = (cot x)tan x
Taking log both the sides:
⇒ log b= log (cot x)tan x
⇒ log b= tan x log (cot x)
{log xa = alog x}
Differentiating with respect to x: