Find , when
y = xx + (sin x)x
let y = x x + (sin x) x
⇒ y = a + b
where a= x x ; b = (sin x) x
a= xx
Taking log both the sides:
⇒ log a= log (x)x
⇒ log a= x log x
{log xa = alog x}
Differentiating with respect to x:
b = (sin x)x
Taking log both the sides:
⇒ log b= log (sin x)x
⇒ log b= x log (sin x)
{log xa = alog x}
Differentiating with respect to x: