Find the equation of the circle with:
Centre (0, - 1) and radius 1.
Given that we need to find the equation of the circle with centre (0, - 1) and radius 1.
We know that the equation of the circle with centre (p, q) and radius ‘r’ is given by:
⇒ (x - p)2 + (y - q)2 = r2
Now we substitute the corresponding values in the equation:
⇒ (x - 0)2 + (y - ( - 1))2 = 12
⇒ (x - 0)2 + (y + 1)2 = 1
⇒ x2 + y2 + 2y + 1 = 1
⇒ x2 + y2 + 2y = 0
∴The equation of the circle is x2 + y2 + 2y = 0.
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