Find the middle term of (1 + 3x + 3x2 + x3)2n.

As (1 + 3x + 3x2 + x3)2n = ((1+x)3)2n


We can write as (1 + x)6n


Here, Total terms are 6n, i.e Even number


Then middle term =


Here, the middle term =


Now,


T3n + 1 = 6nC3n


T3n + 1 =


1