Since, the ordered pairs are equal, the corresponding elements are equal.

∴, a + 3 = 5 …(i) and b – 2 = 1 …(ii)

Solving eq. (i), we get

a + 3 = 5

⇒ a = 5 – 3

⇒ a = 2

Solving eq. (ii), we get

b – 2 = 1

⇒ b = 1 + 2

⇒ b = 3

Hence, the value of a = 2 and b = 3.

(ii) Since, the ordered pairs are equal, the corresponding elements are equal.

∴, a + b = 4 …(i) and 2b – 3 = -5 …(ii)

Solving eq. (ii), we get

2b – 3 = -5

⇒ 2b = -5 + 3

⇒ 2b = -2

⇒ b = -1

Putting the value of b = - 1 in eq. (i), we get

a + (-1) = 4

⇒ a – 1 = 4

⇒ a = 4 + 1

⇒ a = 5

Hence, the value of a = 5 and b = -1.

(iii) Since the ordered pairs are equal, the corresponding elements are equal.

…(i)

…(ii)

Solving Eq. (i), we get

⇒ a = 5 – 3

⇒ a = 2

Solving eq. (ii), we get

⇒ b = 1

Hence, the value of a = 2 and b = 1.

(iv) Since, the ordered pairs are equal, the corresponding elements are equal.

∴, a – 2 = b – 1 …(i)

& 2b + 1 = a + 2 …(ii)

Solving eq. (i), we get

a – 2 = b – 1

⇒ a – b = -1 + 2

⇒ a – b = 1 … (iii)

Solving eq. (ii), we get

2b + 1 = a + 2

⇒ 2b – a = 2 – 1

⇒ -a + 2b = 1 …(iv)

Adding eq. (iii) and (iv), we get

a – b + (-a) + 2b = 1 + 1

⇒ a – b – a + 2b = 2

⇒ b = 2

Putting the value of b = 2 in eq. (iii), we get

a – 2 = 1

⇒ a = 1 + 2

⇒ a = 3

Hence, the value of a = 3 and b = 2.