If A = {x ϵ N : x 3} and {x ϵ W : x < 2}, find (A × B) and (B × A). Is (A × B) = (B × A)?

Given:

A = {x ϵ N: x ≤ 3}


Here, N denotes the set of natural numbers.


A = {1, 2, 3}


[ It is given that the value of x is less than 3 and natural numbers which are less than 3 are 1 and 2]


and B = {x ϵ W: x < 2}


Here, W denotes the set of whole numbers (non – negative integers).


B = {0, 1}


[ It is given that x < 2 and the whole numbers which are less than 2 are 0 and 1]


So, A × B = {1, 2, 3} × {0, 1}


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[By the definition of equality of ordered pairs .i.e. the corresponding first elements are equal and the second elements are also equal, but here the pair (1, 0) is not equal to the pair (0, 1)]


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