Let X = {–1, 0, 2, 5} and f : X → R Z: f(x) = x3 + 1. Then, write f as a set of ordered pairs.
Given, X = {–1, 0, 2, 5}
f : X → R Z: f(x) = x3 + 1
Finding f(x) for each value of x,
(1) f(-1) = (-1)3 + 1 = -1 + 1 = 0
(2) f(0) = (0)3 + 1 = 0 + 1 = 1
(3) f(2) = (2)3 + 1 = 8 + 1 = 9
(4) f(5) = (5)3 + 1 = 125 + 1 = 126
f in ordered pair is represented as
f = {(-1,0),(0,1),(2,9),(5,126)}