Let f : R^{+} → R : f(x) = log_{e} x. Find {x : f(x) = –2}.

Given, f : R^{+} → R : f(x) = log_{e} x

f(x) = -2

log_{e} x = -2

Taking antilog on both sides

x =

Hence , the value of x for which f(x) = -2 is .