Using the principle of mathematical induction, prove each of the following for all n ϵ N:


To Prove:



For n = 1


LHS =


RHS =


Hence, LHS = RHS


P(n) is true for n = 1


Assume P(k) is true


……(1)


We will prove that P(k + 1) is true


RHS =


LHS = [ Writing the Last second term ]


=


= [ Using 1 ]


=


=


= ( Taking LCM and simplifying )


=


= RHS


Therefore, =


LHS = RHS


Therefore, P (k + 1) is true whenever P(k) is true.


By the principle of mathematical induction, P(n) is true for


where n is a natural number


Put k = n - 1


=


Hence proved.


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