Given:

Firstly, we calculate and then find its conjugate

[∵ (a + b)² = a² + b² + 2ab]

[∵ i² = -1]

Now, we rationalize the above by multiplying and divide by the conjugate of 3 – i

…(i)

Now, we know that,

(a + b)(a – b) = (a² – b²)

So, eq. (i) become

[∵ i² = -1]

[∵ i² = -1]

Hence,

So, the conjugate of is