Consider,

Now, rationalizing

In denominator, we use the identity

(a – b)(a + b) = a² – b²

= (i)⁹³ – (-i)³

= (i)⁹²⁺¹ – [-(i)³]

= [(i)⁹²(i)] – [-(i² × i)]

= [(i⁴)²³(i)] – [- (-i)]

= [(1)²³(i)] – i

= i - i

x + iy = 0

∴ x = 0 and y = 0