Solve for x: x2 – 5ix – 6 = 0.
We have, x2 – 5ix – 6 = 0
Here, b2-4ac = (-5i)2-4×1×-6
= 25i2+24 = -25+24 = -1
Therefore, the solutions are given by
Hence, x= 3i and x = 2i