Write –9 in polar form.
we have, z = –9
Let -9 = rcosθ and 0 = rsinθ
By squaring and adding, we get
(-9)2 + (0)2 = (rcosθ)2 + (rsinθ)2
⇒ 81 = r2(cos2θ + sin2θ)
⇒81 = r2
⇒ r = 9
Thus, the required polar form is 9(cos π+i sin π)