Write –9 in polar form.

we have, z = –9

Let -9 = rcosθ and 0 = rsinθ


By squaring and adding, we get


(-9)2 + (0)2 = (rcosθ)2 + (rsinθ)2


81 = r2(cos2θ + sin2θ)


81 = r2


r = 9




Thus, the required polar form is 9(cos π+i sin π)


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