Write –3i in polar form.
Let, z = -3i
Let 0 = rcosθ and -3 = rsinθ
By squaring and adding, we get
(0)2 + (-3)2 = (rcosθ)2 + (rsinθ)2
⇒ 0+9 = r2(cos2θ + sin2θ)
⇒9 = r2
⇒ r = 3
∴ cosθ= 0 and sinθ=-1
Since, θ lies in fourth quadrant, we have
Thus, the required polar form is