we have, z = (1 – i)

Let 1 = rcosθ and -1 = rsinθ

By squaring and adding, we get

(1)² + (-1)² = (rcosθ)² + (rsinθ)²

⇒ 1+1 = r²(cos²θ + sin²θ)

⇒2 = r²

⇒ r = √2

Since, θ lies in fourth quadrant, we have

Thus, the required polar form is