We have to find values of x for which that is is negative

The numerator of is -1 which is negative hence for to be negative x + 2 must be positive (otherwise if x + 2 is negative then negative upon negative will be positive)

That is x + 2 should be greater than 0

⇒ x + 2 > 0

⇒ x > -2

Hence x should be greater than -2 for

x > -2 means x can take values from -2 to ∞ hence x ∈ (-2, ∞)

Hence the solution set for is (-2, ∞)