Solve , when x ϵ R.





Observe that is zero at x = -5 and not defined at x = 5


Hence plotting these two points on number line


Now for x > 5, is positive


For every root and not defined value of the sign will change



We want greater than zero that is the positive part hence x < -5 and x > 5


x < -5 means x is from negative infinity to -5 and x > 5 means x is from 5 to infinity


Hence x (-∞, -5) U (5, ∞)


Hence solution of is x (-∞, 2) U (5, ∞)


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