Given: We have 5 boys and 3 girls

To Find: Number of ways of seating so that 5 boys and 3 girls are seated in a row and each girl is between 2 boys

The formula used: The number of permutations of n different objects taken r at a time (object does not repeat) is

The only arrangement possible is

B__B__B__B__B

Number of ways for boys

=120

There are 3 girls, and they have 4 vacant positions

Number of ways for girls

=24

Total number of ways = 24 × 120 = 2880

In 2880 ways 5 boys and 3 girls can be seated in a row so that each girl is between 2 boys.