In how many ways can 4 girls and 3 boys be seated in a row so that no two boys are together?
The seating arrangement would be like this: B G B G B G B G B So, 4 girls can seat among the four places. Number of ways they can seat is = 4P4 = 24 Boys have to seat among the ‘B’ areas. So, there are 5 seats available for 3 boys. The number of ways the 3 boys can seat among the 5 places is = 5P3 = 60 Therefore, the total number of ways they can seat in this manner is = (24 X 60) = 1440.