How many different committees of 5 can be formed from 6 men and 4 women, if each committee consists of 3 men and 2 women?
Each committee consists of 3 men and 2 women. So, we need to select 3 men out of 6 and 2 women out of 4. The number of ways, 3 men can be selected out of 6, is = 6C3 = 20 The number of ways, 2 women can be selected out of 4, is = 4C2 = 6 So, the totally (20 + 6) = 26 numbers of different committees can be formed.