Let X = {-1, 0, 3, 7, 9} and f : X → R : f(x) x^{3} + 1. Express the function f as set of ordered pairs.

Given: f: X → R, f(x) = x^{3} + 1

Here, X = {-1, 0, 3, 7, 9}

For x = -1

f(-1) = (-1)^{3} + 1 = -1 + 1 = 0

For x = 0

f(0) = (0)^{3} + 1 = 0 + 1 = 1

For x = 3

f(3) = (3)^{3} + 1 = 27 + 1 = 28

For x = 7

f(7) = (7)^{3} + 1 = 343 + 1 = 344

For x = 9

f(9) = (9)^{3} + 1 = 729 + 1 = 730

∴ the ordered pairs are (-1, 0), (0, 1), (3, 28), (7, 344), (9, 730)

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