Let X = {-1, 0, 3, 7, 9} and f : X → R : f(x) x3 + 1. Express the function f as set of ordered pairs.

Given: f: X → R, f(x) = x3 + 1

Here, X = {-1, 0, 3, 7, 9}


For x = -1


f(-1) = (-1)3 + 1 = -1 + 1 = 0


For x = 0


f(0) = (0)3 + 1 = 0 + 1 = 1


For x = 3


f(3) = (3)3 + 1 = 27 + 1 = 28


For x = 7


f(7) = (7)3 + 1 = 343 + 1 = 344


For x = 9


f(9) = (9)3 + 1 = 729 + 1 = 730


∴ the ordered pairs are (-1, 0), (0, 1), (3, 28), (7, 344), (9, 730)


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