Given:

Signs of x – 3

x – 3 = 0 → x = 0 (Adding both the sides by 3)

x – 3 < 0 → x < 3 (Adding both the sides by 3)

x – 3 > 0 → x > 3 (Adding both the sides by 3)

Signs of x + 1

x + 1 = 0 → x = -1 (Subtracting both the sides by 1)

x + 1 < 0 → x < -1 (Subtracting both the sides by 1)

x + 1 > 0 → x > -1 (Subtracting both the sides by 1)

is not defined when x = -1

The interval that satisfies the condition that is -1 < x < 3

Therefore,

x ϵ (-1, 3)